Write the subnet ID, broadcast address and address range of each subnet if you divide a class C network…

Question

Write the subnet ID, broadcast address and address range of each subnet if you divide a class C network 193.168.2.0/24 into 8 different subnets. What is the new subnet mask?

Editorial Team · Accepted Answer

The network is 193.168.2.0/24 (a class C network with 256 addresses). To make 8 subnets we borrow 3 bits from the host part, because 2³ = 8.

New prefix: /24 + 3 = /27
New subnet mask: 255.255.255.224 (11111111.11111111.11111111.11100000)
Host bits left: 5, so each subnet has 2⁵ = 32 addresses, of which 30 are usable hosts.
Block size: 256 − 224 = 32

Subnet	Subnet ID	Usable host range	Broadcast address
1	193.168.2.0	193.168.2.1 – 193.168.2.30	193.168.2.31
2	193.168.2.32	193.168.2.33 – 193.168.2.62	193.168.2.63
3	193.168.2.64	193.168.2.65 – 193.168.2.94	193.168.2.95
4	193.168.2.96	193.168.2.97 – 193.168.2.126	193.168.2.127
5	193.168.2.128	193.168.2.129 – 193.168.2.158	193.168.2.159
6	193.168.2.160	193.168.2.161 – 193.168.2.190	193.168.2.191
7	193.168.2.192	193.168.2.193 – 193.168.2.222	193.168.2.223
8	193.168.2.224	193.168.2.225 – 193.168.2.254	193.168.2.255

The subnet ID (all host bits 0) and the broadcast address (all host bits 1) of each subnet cannot be given to a host.

Write the subnet ID, broadcast address and address range of each subnet if you divide a class C network 193.168.2.0/24 into 8 different subnets. What is the new subnet mask?

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