Study the part of periodic table in which imaginary symbols are given instead of real symbols of elements:…

Question

Study the part of periodic table in which imaginary symbols are given instead of real symbols of elements: Group 1 2 13 14 15 16 17 18 : : : : : : : : : : : : : : : : : Period 2 X Period 3 Y Z M W a) Which one of them is very active non metal? b) Write the electronic configuration of element 'W' on the basis of sub shell. c) Write the reason of being 'Y' more reactive than 'X'. d) Write the balanced chemical equation between the reaction of Z and M.

Padhai · Accepted Answer

a) Very active non‑metal

Symbol	Position (Period‑Group)	Real element	Type
M	Period 3, Group 17	Cl (chlorine)	Very active non‑metal (halogen)

Chlorine is a highly reactive non‑metal because it readily gains one electron to attain a noble‑gas configuration.

b) Electronic configuration of W

W is in Period 3, Group 18 → Ar (argon).
Using the sub‑shell (Aufbau) principle:

$Ar: 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6}$

or in noble‑gas notation

$Ar: [Ne] 3 s^{2} 3 p^{6}$

c) Why Y is more reactive than X

Property	X (Li)	Y (Na)	Reason for higher reactivity of Na
Atomic radius (pm)	152	186	Larger radius → valence electron farther from nucleus
Ionisation energy (kJ mol⁻¹)	520	496	Lower ionisation energy → easier loss of outer e⁻
Shielding effect	Less	More	Increased inner‑electron shielding reduces effective nuclear charge on the valence electron
Position in group	Upper	Lower	Reactivity of alkali metals increases down the group

Thus, Na ( $Y$ ) loses its outer  $3 s^{1}$ electron more readily than Li ( $X$ ), making it more reactive.

d) Balanced chemical equation for the reaction of Z with M

Z = Mg (magnesium) – Period 3, Group 2
M = Cl₂ (chlorine) – Period 3, Group 17 (as diatomic molecule)

The reaction is a synthesis (metal + halogen → metal halide):

$Mg + Cl X_{2} MgCl X_{2}$

Balancing steps

Write the unbalanced formula: $Mg + Cl X_{2} MgCl X_{2}$ .
Count atoms on each side:
- Reactants: Mg = 1, Cl = 2
- Products: Mg = 1, Cl = 2
Both sides already have equal numbers; the equation is balanced.

Final balanced equation: $Mg + Cl X_{2} MgCl X_{2}$ .

Study the part of periodic table in which imaginary symbols are given instead of real symbols of elements: Group 1 2 13 14 15 16 17 18 : : : : : : : : : : : : : : : : : Period 2 X Period 3 Y Z M W…

a) Very active non‑metal

b) Electronic configuration of W

c) Why Y is more reactive than X

d) Balanced chemical equation for the reaction of Z with M

Discussion

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