Write the structural formula of the saturated hydrocarbon having molecular mass 44 amu. Write the IUPAC name of the compound which is obtained by removing two hydrogen atoms from adjacent carbons.

Structural Formula and IUPAC Name of the Hydrocarbon

Step 1: Determine the molecular formula of the saturated hydrocarbon with a molecular mass of 44 amu

Saturated hydrocarbons are alkanes, which follow the general formula: $$\mathrm{C}{}_n\mathrm{H}{}_{2n+2}$$ The molecular mass of an alkane is given by: $$\text{Molecular mass}=12n+1\times (2n+2)=14n+2$$ Given that the molecular mass is 44 amu, we solve for $n$: $$\begin{gathered} 14n+2=44 \\ 14n=42 \\ n=3 \end{gathered}$$ Thus, the molecular formula is $\mathrm{C}{}_3\mathrm{H}{}_8$, which is propane.

Step 2: Draw the structural formula of propane

Propane is a straight-chain alkane with three carbon atoms. Its structural formula is:

propanepropane

Step 3: Remove two hydrogen atoms from adjacent carbons

When two hydrogen atoms are removed from adjacent carbon atoms, a double bond ($\mathrm{C}=\mathrm{C}$) is formed. The resulting compound is an alkene with the formula $\mathrm{C}{}_3\mathrm{H}{}_6$.

The structural formula of the product is:

propenepropene

Step 4: Write the IUPAC name of the compound

The compound formed by removing two hydrogen atoms from adjacent carbons of propane is propene (systematic name: prop-1-ene).

IUPAC name: propene (not propyl or propylene)IUPAC name: propene (not propyl or propylene)

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Final Answer

• Structural formula of the saturated hydrocarbon (C₃H₈):

propanepropane

• IUPAC name of the compound obtained by removing two adjacent hydrogens: Propene (or prop-1-ene).