Nitrogen reacts with oxygen to give N 2O 3 and N 2O 5 respectively. Which law of stoichiometry do this data illustrate ? State the law. [1+1]

Answer

Padhai · Based on the official syllabus and past papers
Updated 10 Oct 2026

The given data illustrates Law of Multiple Proportions.

This law states that if two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element are in the ratio of small whole numbers.

Here, nitrogen reacts with oxygen to form two different oxides: $N X_{2} O X_{3}$ and $N X_{2} O X_{5}$ . The ratio of oxygen atoms combining with a fixed amount of nitrogen (2 atoms) is 3:5, which is a simple whole number ratio.

N₂+O₂Different reaction conditionsFixed mass of N₂ = 2 atomsN₂O₃+N₂O₅

Nitrogen reacts with oxygen to form two distinct oxides: **N₂O₃** and **N₂O₅**, demonstrating the **Law of Multiple Proportions**. The ratio of oxygen atoms per

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