Identify the major products A and B giving their IUPAC names in the given reaction sequence. Methoxy methane [ ]excess HI A Sodium phenoxide B

CH₃OCH₃methoxy methane+2HIexcess HI, ΔCH₃I+CH₃OH

1. Reaction with excess HI: Methoxy methane ($\mathrm{CH}{}_3\mathrm{OCH}{}_3$) undergoes cleavage with excess HI to form iodomethane ($\mathrm{CH}{}_3\mathrm{I}$) as the major product $\mathrm{A}$ (IUPAC name: methanamine is incorrect; the correct product is iodomethane). The reaction proceeds via an $\mathrm{S}{}_{\mathrm{N}}2$ mechanism, breaking the C–O bond and replacing the methoxy group with iodide.

MethylamineMethylamine

2. Reaction with sodium phenoxide: $\mathrm{CH}{}_3\mathrm{I}$ reacts with sodium phenoxide ($\mathrm{C}{}_6\mathrm{H}{}_5\mathrm{ONa}$) in a nucleophilic substitution to form phenol methyl ether ($\mathrm{C}{}_6\mathrm{H}{}_5\mathrm{OCH}{}_3$) as product $\mathrm{B}$ (IUPAC name: methoxybenzene).

CH₃I+C₆H₅ONanucleophilic substitutionanisoleanisole+NaI

Final Products:

• $\mathrm{A}$: Iodomethane ($\mathrm{CH}{}_3\mathrm{I}$)
• $\mathrm{B}$: Methoxybenzene ($\mathrm{C}{}_6\mathrm{H}{}_5\mathrm{OCH}{}_3$)