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Chem Chemistry

ChemistryNEB 2076 (old course)

An alkene A undergoes ozonolysis to give ethanal and methanal as the major products, identify A and write its IUPAC name. [2]

2

Answer

· Based on the official syllabus and past papers
Updated

The alkene A undergoes ozonolysis to yield ethanal (CH₃CHO) and methanal (HCHO) as major products. Ozonolysis cleaves the double bond, forming carbonyl compounds from each carbon of the original alkene.

The products indicate that A must have had the following structure:

  • One carbon of the double bond was bonded to a CH₃ group (from ethanal).
  • The other carbon was bonded to a H atom (from methanal).

Thus, A is propene (CH₃–CH=CH₂). Its IUPAC name is prop-1-ene.

AAO₃, Zn/H₂OStep 1: Ozone cleaves the C=C bond → ozonide → reductive worethanalethanal+methanalmethanal
Ozonolysis of propene (A) yielding ethanal and methanal

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