What happens when [1+1] i) Bleaching powder is treated with dil.H2SO4 ii) Gypsom salt is… – Chemistry NEB 2074 (old course) Solution

i) Bleaching powder treated with $dil \cdot H X_{2} SO X_{4}$

When bleaching powder ( $CaOCl X_{2}$ ) is treated with dilute sulfuric acid ( $H X_{2} SO X_{4}$ ), it undergoes hydrolysis to produce chlorine gas ( $Cl X_{2}$ ), calcium sulfate ( $CaSO X_{4}$ ), and water ( $H X_{2} O$ ). The reaction can be represented as follows:

Sulphuric acidSulphuric acid

Structure of Sulphuric acid

$CaOCl X_{2} + H X_{2} SO X_{4} CaSO X_{4} + H X_{2} O + Cl X_{2}$

Observation:

Chlorine gas ( $Cl X_{2}$ ) is evolved, which has a pungent smell and turns moist blue litmus paper red and then bleaches it.
A white precipitate of calcium sulfate ( $CaSO X_{4}$ ) is formed.

ii) Gypsum salt heated above $13 0^{\circ} C$

When gypsum ( $CaSO X_{4} \cdot 2 H X_{2} O$ ) is heated above $13 0^{\circ} C$ , it loses its water of crystallization and forms plaster of Paris ( $CaSO X_{4} \cdot \frac{1}{2} H X_{2} O$ ). The reaction is as follows:

$CaSO X_{4} \cdot 2 H X_{2} O > 130 X^{\circ} C CaSO X_{4} \cdot \frac{1}{2} H X_{2} O + \frac{3}{2} H X_{2} O$

Observation:

The solid turns into a powdery form (plaster of Paris).
Water vapor is released.
Plaster of Paris hardens on mixing with water, forming a solid mass.

What happens when [1+1] i) Bleaching powder is treated with dil.H2SO4 ii) Gypsom salt is heated above 130^ .

i) Bleaching powder treated with $dil \cdot H X_{2} SO X_{4}$

ii) Gypsum salt heated above $13 0^{\circ} C$

Discussion

More Chemistry questions

What happens when [1+1] i) Bleaching powder is treated with dil.H2SO4 ii) Gypsom salt is heated above 130^ .

i) Bleaching powder treated with dil⋅HX2​SOX4​

ii) Gypsum salt heated above 130∘C

Discussion

More Chemistry questions

i) Bleaching powder treated with $dil \cdot H X_{2} SO X_{4}$

ii) Gypsum salt heated above $13 0^{\circ} C$