ChemistryNEB 2074 (old course) (grade increment)

What is the effect of increase of pressure and decrease of temperature in the following chemical equilibrium ? 2SO2 (g) + O2 (g) <= 2SO3 (g) + heat

2

Answer

The given reaction is an exothermic reaction where the forward reaction is favoured by the application of pressure and lowering of temperature.

Effect of Increase of Pressure:

  • The reaction involves 3 moles of gaseous reactants and 2 moles of gaseous products.
  • According to Le Chatelier’s principle, increasing the pressure shifts the equilibrium in the direction where the number of moles of gas decreases.
  • Thus, the equilibrium shifts to the right, producing more .
00.751.52.253Reactants (3 moles gas)3Products (2 moles gas)2Total moles of gas
Pressure effect: Fewer gas moles favor forward reaction (2SO₂ + O₂ → 2SO₃)
22SO₂+O₂Pressure ↑Moles of gas: 3 → 222SO₃
Effect of increasing pressure: fewer moles of gas → equilibrium shifts right (2SO₂ + O₂ → 2SO₃)

Effect of Decrease of Temperature:

  • The reaction is exothermic, meaning heat is released during the forward reaction.
  • Lowering the temperature removes heat from the system, and the equilibrium shifts in the direction that produces heat.
  • Hence, the equilibrium shifts to the right, producing more .
22SO₂+O₂Temperature ↓Shift: ← (endothermic) → (exothermic)22SO₃
Effect of decreasing temperature on exothermic equilibrium (2SO₂ + O₂ ⇌ 2SO₃ + heat)

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